SOLUTION: FIND THE EQUATION OF THE PARABOLA WITH VERTICAL AXIS THAT PASSES THROUGH THE POINT (0,2) AND THE POINTS OF INTERSECTION OF THE PARABOLAS x² + 2x + 3y + 4 = 0 AND x²- 3x + y+ 3 =

Question 1187080: FIND THE EQUATION OF THE PARABOLA WITH VERTICAL AXIS THAT PASSES THROUGH THE POINT (0,2) AND THE POINTS OF INTERSECTION OF THE PARABOLAS x² + 2x + 3y + 4 = 0 AND x²- 3x + y+ 3 = 0.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

vertical axis passes through (,)
find the points of intersection of the parabolas
...........eq.1
........eq.2
------------------------------------sumtract eq.2 from eq.1

.............solve for

go to
........eq.2, substitute
........ solve for , multiply by

............factor

solutions: ,

go to
, substitute

intersection points are: (,) and (,)
and to find parabola containing the three points (,), (,) and (,), you could setup three equations using these points starting in a format

.........1)

..........divide by and solve for
...............2)

....... multiply by andsolve for

....3)
equal 2) and 3)
......solve for

then
...............2)

your equation is
......substitute ,,

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