SOLUTION: Dear Sir, Please help me solve this problem and kindly show me your solution. Find the general equation of the of the parabola with vertex at (5, −3) and focus at (6, −3)

Question 1181164: Dear Sir,
Please help me solve this problem and kindly show me your solution.
Find the general equation of the of the parabola with vertex at (5, −3) and focus at (6, −3).
Sketch and determine the parts of the parabola.
Solve the value for C
Parts of the Parabola
Parts of the Parabola
1. Vertex
2. Focus
3. Directrix
4. Axis of Symmetry
5. 𝑬𝟏
𝑬𝟐
6. Length of 𝐸1, 𝐸2
7. Graph
Thank you very much.
And more power.
Sincerely yours,
Lorna
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

given:

Vertex at (,) => and
focus at (,)
noticed that focus and vertex lie on the same horizontal line
parabola open to the right and the standard equation is:

Distance from vertex to focus is

Parts of the Parabola
1. Vertex is at (,)
2. Focus is at (,)
3. Directrix:
4. Axis of Symmetry:
5.
use (,), E1, E1 will be where a line intersect parabola
...plug in

or
or
or
E1=(,), E1=(,)
6. Length of E1, E2 is distance between (,) and (,), and it is

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