SOLUTION: Dear Sir/Ma'am, Please help me solve this problem Find the General Equation of the Parabola with Vertex at (5,3) and focus at (6,-3). Sketch and determine the parts of the Pa

Question 1181022: Dear Sir/Ma'am,
Please help me solve this problem
Find the General Equation of the Parabola with Vertex at (5,3) and focus at (6,-3). Sketch and determine the parts of the Parabola
Parts of the Parabola
1. Vertex
2. Focus
3. Directrix
4. Axis of Symmetry
5. E1, E1
6. Length of E1, E2
Thank you very much. More Power and God bless you.
Sincerely yours,
Lorna

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
the standard equation for an up-down facing parabola:

given:
Vertex at (,) => and
so far, equaion is

and given focus at (,)=> I believe it is not because focus and verex must lie on same line
use it to calculate
since F(,)
if =>=>
and your equation is:

Sketch and determine the parts of the Parabola

Parts of the Parabola
1. Vertex is at (,)
2. Focus is at (,)
3. Directrix: =>=>=>
4. Axis of Symmetry:
5. use (,), E1, E1 will be where a line intersect parabola
...plug in

, when
, when
E1=(,), E1=(,)
6. Length of E1, E2 is distance between (,) and (,), and it is

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