SOLUTION: Find the equation of the parabola with vertex at (2, -1) and directrix y+2=0. Sketch the graph.

Algebra.Com
Question 1170411: Find the equation of the parabola with vertex at (2, -1) and directrix y+2=0. Sketch the graph.
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
That is directrix y=-2, and vertex (2,-1). These are 1 unit apart at their nearest points. Focus must be 1 unit above the vertex so focus is at (2,0). Do a quick sketch of these focus, vertex, and directrix. These indicate that vertex is a minimum.

You could form your equation based on .

;


RELATED QUESTIONS

Given the equation of the parabola (x+2)^2=2(y-1), find the vertex, directrix, focus and... (answered by josgarithmetic)
Find the vertex, focus and directrix of the parabola and sketch the graph... (answered by josgarithmetic)
x^2+8x-y+6=0 Find the vertex, focus, and directrix of the parabola. Sketch the... (answered by Nate)
Find the equation of the parabola with vertex at (−2, 2) and directrix at y =... (answered by nyc_function)
find the vertex, focus, and directrix of the parabola given by each equation. Sketch the... (answered by josgarithmetic)
find the vertex, focus, and directrix of the parabola and sketch its graph. the equation (answered by richwmiller)
Find the vertex, focus, and directrix of the parabola given by each equation. Sketch the (answered by stanbon)
Find the length of the latus rectum and the equation of the parabola with vertex at the... (answered by CPhill)
find the vertex, focus, and directrix of the parabola given by each equation. Sketch the... (answered by josgarithmetic)