SOLUTION: Find the vertex and directrix of 2x^2+4y-8=0

SOLUTION: Find the vertex and directrix of 2x^2+4y-8=0

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Question 1167982: Find the vertex and directrix of
2x^2+4y-8=0
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!

vertex is at (0,2).

Since parabola opens downward with vertex maximum, directrix is at .
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