SOLUTION: (a)Given the equation of a conic section as:
9x² + 25y² − 36x − 150y + 36 = 0.
(i) Express the equation in standard form.
Algebra.Com
Question 1160940: (a)Given the equation of a conic section as:
9x² + 25y² − 36x − 150y + 36 = 0.
(i) Express the equation in standard form.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ +\ 25\(y^2\,-\,6\,+\,9\)\ =\ -36\ +\ 36\ +\ 225)
^2\ +\ 25(y\ -\ 3)^2\ =\ 225)
^2}{25}\ +\ \frac{(y\ -\ 3)^2}{9}\ =\ 1)
John
My calculator said it, I believe it, that settles it
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