SOLUTION: One piece of ash was ejected from a volcano with a initial velocity of 336ft/sec. The heigh H in feet is given by the equation H=-16t^2+336t where T is the time in seconds.
When d
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Question 1160350: One piece of ash was ejected from a volcano with a initial velocity of 336ft/sec. The heigh H in feet is given by the equation H=-16t^2+336t where T is the time in seconds.
When does the ash projectile reach its maximim height?
It's the vertex of the parabola at t = -b/2a
Solve for t
==================================
What is its maximum height?
Sub t at the vertex.
=========================
when does the ash projectile return to the ground?
When -16t^2 + 336t = 0
Which is 2 times the t at the vertex.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
where is the time in seconds.
When does the ash projectile reach its maximum height?
It's the vertex of the parabola at
in your case and
then
What is its maximum height?
Sub at the vertex.
max at
when does the ash projectile return to the ground?
When
Which is times the at the vertex
at the vertex:
times the at the vertex:
the ash projectile return to the ground in seconds
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