From the condition, the roots of the quadratic function are x= 2 and x= 5. Therefore, the quadratic form in factored form is y(x) = a*(x-2)*(x-5), where "a" is an arbitrary (now unknown) real number. To find the value of "a", use the condition y(1) = 8, which leads to the equation a*(1-2)*(1-5) = 8, or a*(-1)*(-4) = 8, 4a = 8, a == 2. The final factorized form of the given quadratic function is y(x) = 2*(x-1)*(x-5).