SOLUTION: Find the value/s of U so that the graph of the equation of Ux^2 + y^2 − 2Ux = 0 is a hyperbola. Afterwards, identify the distance/s between the foci.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the value/s of U so that the graph of the equation of Ux^2 + y^2 − 2Ux = 0 is a hyperbola. Afterwards, identify the distance/s between the foci.      Log On


   



Question 1152644: Find the value/s of U so that the graph of the equation of Ux^2 + y^2 − 2Ux = 0 is a hyperbola.
Afterwards, identify the distance/s between the foci.

Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
Find the value/s of U so that the graph of the equation of
Ux^2 + y^2 − 2Ux = 0 is a hyperbola.
Afterwards, identify the distance/s between the foci.
That will be the equation of a hyperbola if you pick any negative number
for U.  The easiest negative number to pick for U is -1:

Ux%5E2+%2B+y%5E2+%E2%88%92+2Ux+=+0

%28-1%29x%5E2+%2B+y%5E2+%E2%88%92+2%28-1%29x+=+0

-x%5E2+%2B+y%5E2+%2B+2x+=+0

y%5E2+-+x%5E2+%2B+2x+=+0

Write y² as (y-0)² and factor out a negative from the two terms in x:

%28y-0%29%5E2+-+%28x%5E2-2x%29=0

Complete the square by adding +1 inside the parentheses, which
amounts to adding -1 to the left side, so add -1 to the right
side also:

%28y-0%29%5E2+-+%28x%5E2-2x%2B1%29=-1

We write the second parentheses as the square of a binomial:

%28y-0%29%5E2+-+%28x-1%29%5E2=-1

Since the right side is negative, we multiply through by -1

-%28y-0%29%5E2+%2B+%28x-1%29%5E2=%2B1

We reverse the terms on the left:

%28x-1%29%5E2+-+%28y-0%29%5E2=1

We put 1's under the two terms on the left:

%28x-1%29%5E2%2F1%5E%22%22+-+%28y-0%29%5E2%2F1%5E%22%22=1




We compare 

%28x-1%29%5E2%2F1%5E%22%22+-+%28y-0%29%5E2%2F1%5E%22%22=1 to

%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2=1

The center is (h,k) = (1,0), a=1, b=1,

We calculate c, the distance fro center to foci from 

c%5E2=a%5E2%2Bb%5E2
c%5E2=1%5E2%2B1%5E2
c%5E2=1%2B1
c%5E2=2
c=sqrt%282%29

So the foci are %28matrix%281%2C3%2C1%2Bsqrt%282%29%2C%22%2C%22%2C0%29%29 and %28matrix%281%2C3%2C1-sqrt%282%29%2C%22%2C%22%2C0%29%29,

so the distance between the foci is

2sqrt%282%29

If you chose any other negative number for U the answer would be different.

Edwin