SOLUTION: put the equation 16x^2+y^2+64x-2y+67=0 into conic standard form

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Question 1151192: put the equation 16x^2+y^2+64x-2y+67=0 into conic standard form
Found 3 solutions by Edwin McCravy, MathLover1, ikleyn:
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!


Swap the 2nd and 3rd terms on the left to get the terms together
for each letter:

 

Subtract the constant term from both sides:





Factor out 16 out of the first two terms, and 1 out of
the last two terms:



We complete the square inside the first parentheses:
1. Multiply the coefficient of x, which is 4, by one-half, getting 2.
2. Square 2, getting 4.
3. Add +4 at the end of the first parentheses.
4. Since the number in front of the parentheses is 16, adding 4 inside
   the parentheses amounts to adding 16∙4 or 64 to the left side, so
   we add 64 to the right side:



We complete the square inside the second parentheses:
1. Multiply the coefficient of y, which is -2, by one-half, getting -1.
2. Square -1, getting +1.
3. Add +1 at the end of the first parentheses.
4. Since the number in front of the parentheses is 1, adding 4 inside
   the parentheses amounts to adding 1∙1 or 1 to the left side, so
   we add 1 to the right side:



Next we factor the quadratics in the parentheses:





This does not represent a conic because the left side is positive
and the right side is negative.  

We get 1 on the right side by dividing each term by -2





We divide top and bottom of the first fraction by 16







If this were a real conic, there would not be a negative number
on the bottom of either term, but only positive numbers.

Did you copy the problem wrong?

Edwin

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

put the equation into conic standard form=> here is an error, to have conic, must be


.......group like terms
............complete squares





.... move to the right
...switch sides
........both sides divide by
..........write in front of part as
=> here you have the equation of hyperbola in conic standard form

Answer by ikleyn(52802)   (Show Source): You can put this solution on YOUR website!
.

Edwin just derived this standard conic equation for you


     +  = -1.


This equation describes the empty set of points.


Indeed, the equation has the left side non-negative (as the sum of two squares), while its right side is the negative number,

so the equation has no real solutions.


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