SOLUTION: Common tangents are drawn to parabola y²=4x and ellipse 3x²+8y²=48 touching the parabola at A & B and the ellipse at C & D.Find the area of quadrilateral
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-> SOLUTION: Common tangents are drawn to parabola y²=4x and ellipse 3x²+8y²=48 touching the parabola at A & B and the ellipse at C & D.Find the area of quadrilateral
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Question 1149909: Common tangents are drawn to parabola y²=4x and ellipse 3x²+8y²=48 touching the parabola at A & B and the ellipse at C & D.Find the area of quadrilateral Answer by Edwin McCravy(20059) (Show Source):
We must find all the points of tangency.
I'll assume you haven't had calculus, it's a lots harder that way! lol.
Let the common tangent line have equation y=mx+b, solve the system
and find the discriminant of the resulting quadratic to be 1-bm. Set it equal to
0, because there is only one solution at a tangent point. Then solve the
system:
and find the discriminant of the resulting quadratic to be -b²+16m²+6. Set it
equal to 0. Then solve the system
You'll get
Substitute the positive values for b and m in y=mx+b, and solve simultaneously
with the parabola and get:
and you can tell by symmetry that
and with the ellipse and get:
and you can tell by symmetry that
The quadrilateral CDBA is a trapezoid (or trapezium if you live in the UK).
The height is along the x-axis from -2 to 8 which is 10 units.
It's much easier If you've had calculus. Just equate the derivatives to find the
values of x where the slopes are the same. You'll get the same answer.
Edwin