SOLUTION: Given y=3x^2+6x Please explain the process in steps. Thanks! A.) find the y-intercept B.) find the x-intercepts (if any) c.) find the vertex D.) Sketch the parabola.

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Question 114528: Given y=3x^2+6x
Please explain the process in steps. Thanks!
A.) find the y-intercept
B.) find the x-intercepts (if any)
c.) find the vertex
D.) Sketch the parabola.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Given:

find:
A.) find the …………
find the we need to set equal to



B.) find the (if any)
To find the , set equal and solve:

or

……………. In this quadratic equation factor out
…………….find solutions
Above product will be equal to if either one or both factors are equal to
So is
is , and this will be true if } =>
Or
Therefore, are at and

c.) find the

Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form


Start with the given equation



Subtract from both sides



Factor out the leading coefficient



Take half of the x coefficient to get (ie ).


Now square to get (ie )





Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of does not change the equation




Now factor to get



Distribute



Multiply



Now add to both sides to isolate y



Combine like terms




Now the quadratic is in vertex form where , , and . Remember (h,k) is the vertex and "a" is the stretch/compression factor.




Check:


Notice if we graph the original equation we get:


Graph of . Notice how the vertex is (,).



Notice if we graph the final equation we get:


Graph of . Notice how the vertex is also (,).



So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.






D.) Sketch the parabola.
See

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