SOLUTION: Find the equation of the hyperbola with the following properties. Foci at (5,-4) and (13,-4) Vertices at (6,-4) and (12,-4)

Question 1144011: Find the equation of the hyperbola with the following properties.
Foci at (5,-4) and (13,-4)
Vertices at (6,-4) and (12,-4)

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

(1) Foci at (5,-4) and (13,-4)

So...

Transverse axis is horizontal, so branches open right and left.
The general equation is .
The center (h,k) is halfway between the foci, at (9,-4).
c=4.

(2) Vertices at (6,-4) and (12,-4)

So the length of the transverse axis is 6, which means a=3.

Use c^2=a^c+b^2 to determine a^2; then write the equation.
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