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Each of the two focuses of an ellipse is located on its major axis at the distance of c = from its center,
where "a" is the major semi-axis of the ellipse and "b" is its minor semi-axis.
In the given case, a = = 46 ft, b = = 29 ft, so
the distance from the center of the ellipse to any of the two its focuses is
c = = 35.707 ft.
The distance between the focuses is two times this value, i.e. 2*35.707 = 71.14 ft. ANSWER
Solved.
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For this and other remarkable properties of ellipses see the lessons
- Ellipse definition, canonical equation, characteristic points and elements
- Ellipse focal property
- Tangent lines and normal vectors to a circle
- Tangent lines and normal vectors to an ellipse
- Optical property of an ellipse
- Optical property of an ellipse revisited
in this site.