SOLUTION: Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. Horizontal axis and passes through the point (−2, 5)

Question 1136722: Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin.
Horizontal axis and passes through the point (−2, 5)
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
, horizontal symmetry axis, vertex (h,k)

, vertex is (0,0).

, using the given point on the parabola.

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

y=ax^2 has a vertical axis of symmetry; a horizontal axis of symmetry with vertex at the origin means the equation is x = ay^2.

Find the value of a by substituting the coordinates of the given point in the equation.

The equation is

A graph, showing the parabola passing through (-2,5)...

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