SOLUTION: We are given the following equation: f(x)=x^2+25, and are asked to find the Vertex and the X-intercept(s).
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Question 1128688: We are given the following equation: f(x)=x^2+25, and are asked to find the Vertex and the X-intercept(s).
Found 2 solutions by josmiceli, MathLover1:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The x-intercept(s) is where , so
and, also,
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There are 2 imaginary x-intercepts, and no
real x-intercepts
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Using the general form:
The x-value of the vertex is at:
where
Plug this back into equation:
The vertex is at ( 0,25 )
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Here's the plot:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
, => parabola, opening up, has minimum
to find the Vertex, find minimum; set
minimum or vertex is at (,)
and to find the -intercept(s), set
or => there is no -intercept(s)
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