SOLUTION: The circle given by x^2+y^2-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21. What is the value of k in this solution?
Algebra.Com
Question 1128402: The circle given by x^2+y^2-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21. What is the value of k in this solution?
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
RELATED QUESTIONS
if x+y^2+kxy+8x-6y+9=0 represents a circle state the value of k and substituting this... (answered by KMST)
Place in standard form for the circle ( which is (x-h)^2 + (y-k)^2 = r^2):
x^2 + y^2 +... (answered by ewatrrr)
find the value of k so that x^2+y^2+4x-6y+k=0 is the equation of circle of radius... (answered by josgarithmetic)
what is the standard form, radius, and center of this circle equation:... (answered by Fombitz)
The following equation is the general form of the circle
2x^2 - 5x + 2y^2 - 7y = 0.... (answered by Theo)
Show that the quadratic function {{{y=ax^2+bx+c}}} can be written in the form... (answered by fcabanski)
what is the value of k in x^2+y^2-6x+8y+5=k in a circle, a point, and an empty set?... (answered by Fombitz)
what is this equation written in vertex x2 + 6x - 2(Be sure to write your response in the (answered by fractalier)
Let k be a positive real number. The line x + y = k/2 and the circle x^2 + y^2 = 3x - 6y... (answered by CPhill)