.
According to the condition, the ellipse (or semi-ellipse) semi-minor and semi-major axes are 5 m and 16/2 = 8 m, respectively.
Hence, the linear eccentricity is = 6.245 m.
It is the distance from the center of the semi-ellipse to its focuses.
Answer. The two friends should stay at the focuses of the ellipse that are located at the distance of 6.245 m from the center of the ellipse.
P.S. To be exactly precise, the two friends should LIE on the floor at that locations to have their mouths and their ears
maximally close to the focuses :-).
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For relevant lessons, see
- Ellipse definition, canonical equation, characteristic points and elements
- Ellipse focal property
- Tangent lines and normal vectors to a circle
- Tangent lines and normal vectors to an ellipse
- Optical property of an ellipse
- Optical property of an ellipse revisited
- Practical problems from the archive related to ellipses and parabolas
Also, you have this free of charge online textbook in ALGEBRA-II in this site
ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic
"Conic sections: Ellipses. Definition, major elements and properties. Solved problems".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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Comment from student : Thank you so much maam. How about the letter B?
My response : I answered both questions. Read my answer attentively . . .