SOLUTION: Can someone help me? How to write the equation in polar form?
y^2+8x-16=0
Thank you.
Algebra.Com
Question 1110627: Can someone help me? How to write the equation in polar form?
y^2+8x-16=0
Thank you.
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
substitute y with rsinθ and x with rcosθ:
(rsinθ)^2 + 8rcosθ - 16 = 0
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