SOLUTION: ellipse and hyperbola Find the coordinates of the vertices 4y^2

SOLUTION: ellipse and hyperbola Find the coordinates of the vertices 4y^2 - 38x^2 = 144

Question 1108705: ellipse and hyperbola
Find the coordinates of the vertices
4y^2 - 38x^2 = 144
Answer by ikleyn(52802) (Show Source): You can put this solution on YOUR website!
.

It is a hyperbola with y-axis as a real axis.


The center is at (0,0), the origin of the coordinate plane.


The vertices are the points of the curve lying at y-axis  x= 0.


So, substitute x= 0 into the equation and get  4y^2 = 144,


which implies  y^2 =  = 36,  y = +/- = +/-6.


So the vertices are  (0,6)  and  (0,-6).

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