SOLUTION: how to find the radius and center of 25x^2+25y^2-20x+30y+13=0

Question 1101114: how to find the radius and center of 25x^2+25y^2-20x+30y+13=0

Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!

This is not a circle, has no radius, but center is at (2/5, -3/5).
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
how to find the radius and center of 25x^2+25y^2-20x+30y+13=0
---------
Complete the squares of x & y separately
---

The r^2 term is negative.
Not a circle.
Typo maybe?
---------
RELATED QUESTIONS
how is the steps done for these? Find the centre and the radius of 1.)25x^2+25y^2=25 (answered by solver91311,MathLover1)
Solve by factoring and using the principle of zero products. 25y^2 + 30y + 8 = 0 (answered by htmentor)
{{{ 25y^2-4x^2-8x-104=0 }}} Idk how to find the center teach me please (answered by purpleoj)
I need to find the center,vertices, and foci of the ellipse... (answered by Edwin McCravy)
Find the binomial factors for the following trinomial and check using the FOIL method. (answered by RAY100)
FACTOR EACH COMPLETELY 24xy+25y^2-20x-30y^3 please show... (answered by Edwin McCravy)
Find the center, the vertices, and the foci of the ellipse... (answered by lwsshak3)
4x^2+25y^2-8x+100y+4=0 find the center, vertices and foci of the ellipse (answered by lwsshak3)