SOLUTION: Alright, so I'm supposed to solve this equation algebraically, but I'm not sure what the last step is. Like how to show the answer. So here's the answer I got... {{{-3x^2-2x+1<0

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Alright, so I'm supposed to solve this equation algebraically, but I'm not sure what the last step is. Like how to show the answer. So here's the answer I got... {{{-3x^2-2x+1<0       Log On

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Question 109687: Alright, so I'm supposed to solve this equation algebraically, but I'm not sure what the last step is. Like how to show the answer. So here's the answer I got... -3x%5E2-2x%2B1%3C0%0D%0Ax=%282%2Bor-sqrt%284%2B12%29%29%2F%282%2A-3%29%0D%0A+++++++++++++++=++%282%2Bor-sqrt%2816%29%29%2F%28-6%29%0D%0A++++++++++=%282%2Bor-4%29%2F%28-6%29%0D%0A++++++++++++x=-1+++or++++=1%2F3+
Is that it?

Answer by ankor@dixie-net.com(12706) About Me  (Show Source):
You can put this solution on YOUR website!
algebraically, but I'm not sure what the last step is. Like how to show the answer. So here's the answer I got... -3x^2-2x+1<0
x=(2+or-sqrt(4+12))/(2*-3)
= (2+or-sqrt(16))/(-6)

:
x =%282%2Bor-4%29%2F%28-6%29
You are right but at this point, I would separate the two solutions:
x = %282-4%29%2F%28-6%29
x = %28-2%29%2F%28-6%29
x = +1%2F3
and
x = %282+%2B+4%29%2F%28-6%29
x = 6%2F%28-6%29
x = -1


x=-1 or =1/3