SOLUTION: Find the center, vertices, and foci of the ellipse with equation x^2/400 + y^2/256 = 1.

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Question 1094664: Find the center, vertices, and foci of the ellipse with equation x^2/400 + y^2/256 = 1.

Answer by ikleyn(52802)   (Show Source): You can put this solution on YOUR website!
.
Center is at (0,0).


Vertices  (-20,0), (20,0),  (0,16)  and  (0,-16).


Ellipse is wider than tall.


Linear eccentricity is  c =  =  = 12.


Foci are at (-12,0)  and  (12,0).


See the lessons
    - Ellipse definition, canonical equation, characteristic points and elements

    - Standard equation of an ellipse
    - Identify elements of an ellipse given by its standard equation
    - Find the standard equation of an ellipse given by its elements
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Conic sections: Ellipses. Definition, major elements and properties. Solved problems".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.



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