SOLUTION: Graph the parabola and clearly indicate the focus, directrix, and the endpoints at the latus rectum (x+3)^2 = 8(y+2) PS. Thank you in advance!!

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Graph the parabola and clearly indicate the focus, directrix, and the endpoints at the latus rectum (x+3)^2 = 8(y+2) PS. Thank you in advance!!       Log On


   

Question 1091497: Graph the parabola and clearly indicate the focus, directrix, and the endpoints at the latus rectum
(x+3)^2 = 8(y+2)
PS. Thank you in advance!!
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The equation gives you most of the information already.

8%28y%2B2%29=%28x%2B3%29%5E2, axis of symmetry is vertical. Vertex is a minimum point of the parabola.
VERTEX (-3,-2)
p, distance between vertex and either directrix or focus;
4p=8, p=2
FOCUS (-3,0)
DIRECTRIX y=-4.

If solve for x when y is 0, find zeros at x=-7 and x=1.



graph%28300%2C300%2C-11%2C5%2C-8%2C8%2C-2%2B%281%2F8%29%28x%2B3%29%5E2%29