SOLUTION: Equation of a circle Passing through (6,-1) and tangent 4y-3x-2=0 at (2,2)
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Question 1089733: Equation of a circle Passing through (6,-1) and tangent 4y-3x-2=0 at (2,2)
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Equation of a circle Passing through (6,-1) and tangent 4y-3x-2=0 at (2,2)
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A(6,-1) and B(2,2) are 2 points on the circle.
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Find the equation on the line thru (2,2) and perpendicular to the line 4y-3x-2=0.
The center of the circle is on that line.
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Find the perpendicular bisector of AB.
The center of the circle is on that line.
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The intersection of the 2 lines is the center.
The distance from the center to either point is the radius.
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email via he TY note for help, or to check you work.
Answer by ikleyn(52852) (Show Source): You can put this solution on YOUR website!
.
You can find many similar solved problems/samples in the lesson
- Find the standard equation of a circle
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic
"Conic sections: Ellipses. Definition, major elements and properties. Solved problems".
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