SOLUTION: hi! I'm not sure how to do this word problem of a parabola. The question is: An arch is the shape of a parabola. If an arch is 200 feet high and 80 feet wide, how tall is the arch

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: hi! I'm not sure how to do this word problem of a parabola. The question is: An arch is the shape of a parabola. If an arch is 200 feet high and 80 feet wide, how tall is the arch       Log On


   



Question 1089467: hi! I'm not sure how to do this word problem of a parabola. The question is: An arch is the shape of a parabola. If an arch is 200 feet high and 80 feet wide, how tall is the arch at 20 feet away from the center. Thank you!
Answer by ikleyn(52800) About Me  (Show Source):
You can put this solution on YOUR website!
.
For simplicity, let assume that the origin of the coordinate system is placed on the ground EXACTLY at the symmetry line of the parabola.


Then the equation of the parabola in this coordinate system is 

y = a*(x+40)*(x-40) = a%2A%28x%5E2+-+40%5E2%29 = a%2A%28x%5E2-1600%29,

where 40 is half the distance between the arc's foots, and "a" is some unknown coefficient.


You need to choose the value of "a" in a way to provide its arc height 200 ft at x = 0. So, your equation for "a" is

200 = a%2A%280%5E2+-+1600%29 = -a*1600,

which gives you  a = 200%2F%28-1600%29 = -1%2F8.


Thus your parabola is  y = %28-1%2F8%29%2A%28x%5E2-1600%29.     (1)


Now to find the height at x = 20 ft, you need simply substitute x= 20 into the formula (1).  You will get


    The height of the arc at x= 20  is  y = %28-1%2F8%29%2A%2820%5E2-1600%29 = %28-1%2F8%29%2A%28400-1200%29 = %28-1%2F8%29%2A%28-800%29 = 100 ft.


Answer.  The height of the arc at x= 20  is  100 ft.

Solved.