SOLUTION: 289(x−12)2+64(y−3)2=1

Question 1087046: 289(x−12)2+64(y−3)2=1

Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
.

 +  = 1.

Equivalently

 +  = 1,    which is the same as 

 +  = 1. 


Ellipse with the center at (x,y) = (12,3).


The major axis is vertical. The ellipse is taller than wide.


The major (vertical)   semi-axis has the length of a =  of unit.

The minor (horizontal) semi-axis has the length of b =  of unit.

The linear eccentricity is c =  =  = .


Having this, you can easily determine the foci of the ellipse.

See the lessons
    - Ellipse definition, canonical equation, characteristic points and elements

    - Standard equation of an ellipse
    - Identify elements of an ellipse given by its standard equation
    - Find the standard equation of an ellipse given by its elements

    - General equation of an ellipse
    - Transform a general equation of an ellipse to the standard form by completing the square
    - Identify elements of an ellipse given by its general equation

    - OVERVIEW of lessons on ellipses

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Conic sections: Ellipses. Definition, major elements and properties. Solved problems".

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SOLUTION: &#8203;289&#8203;&#8203;(x&#8722;12)&#8203;2&#8203;&#8203;&#8203;&#8203;+&#8203;64&#8203;&#8203;(y&#8722;3)&#8203;2&#8203;&#8203;&#8203;&#8203;=1

SOLUTION: 289(x−12)2+64(y−3)2=1