SOLUTION: find the focus of x^2+4y^2+2x+24y++28=0

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Question 1086650: find the focus of x^2+4y^2+2x+24y++28=0
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
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find the focus of x^2+4y^2+2x+24y++28=0
~~~~~~~~~~~~~~~~~~~~~~~~~~~

I don't know what "++" means; will assume that it is "+".

  ===> (I will complete the squares for x-terms and y-terms separately)  ====>  

 = ,

 +  = ,

 +  = ,

 +  = ,

 +  = 1.






Ellipse  +  = 1



The center of the ellipse is at (x,y) = (-1,-3).


The ellipse has the horizontal major axis.


The major semi-axis is 3 units long.


The minor semi-axis is  = 1.5 units long.


The linear eccentricity is  = .


The foci are at  (,)  and  (,).

For more details, see the lessons
    - Ellipse definition, canonical equation, characteristic points and elements

    - General equation of an ellipse
    - Transform a general equation of an ellipse to the standard form by completing the square
    - Identify elements of an ellipse given by its general equation


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Conic sections: Ellipses. Definition, major elements and properties. Solved problems".



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