SOLUTION: Angle substended by the common tangents of two ellipses 4(x-4)2+25y2=100 and 4(x+1)2+y2=4 at the origin is

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Angle substended by the common tangents of two ellipses 4(x-4)2+25y2=100 and 4(x+1)2+y2=4 at the origin is       Log On


   

Question 1086578: Angle substended by the common tangents of two ellipses 4(x-4)2+25y2=100 and 4(x+1)2+y2=4 at the origin is
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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Angle substended by the common tangents of two ellipses 4(x-4)2+25y2=100 and 4(x+1)2+y2=4 at the origin is
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Ellipse 4%2A%28x-4%29%5E2+%2B+25y%5E2 = 100 and ellipse 4%28x%2B1%29%5E2%2By%5E2 = 4.



I made the work of drawing these ellipses.

After getting the plots, I make a statement:   THIS POST IS NONSENSE.

In other words,    I T    D O E S    N O T    M A K E    S E N S E.


All other tutors can save their valuable time looking in these plots.


What else one may expect from the person who writes "Angle substended . . . "