SOLUTION: How do I use the elimination method to solve this problem? 3x^2+4y^2=48 2x^2-y^2=-1

Question 1076997: How do I use the elimination method to solve this problem?
3x^2+4y^2=48
2x^2-y^2=-1
Found 3 solutions by josgarithmetic, Alan3354, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Exactly as you already learned.

Eliminate the
Multiply E1 by 2 and multiply E2 by 3; subtract either equation from the other.

Eliminate
Just multiply E2 by 4; and add the two equations.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Multiply the 2nd equation by 4 then add the equations.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

How do I use the elimination method to solve this problem?
3x^2+4y^2=48
2x^2-y^2=-1

------ eq (i)
------ eq (ii)
Multiply eq (ii) by 4 to get eq (iii)
Add eqs (iii) & (i) to eliminate
You'll get 2 values for x. Likewise, you'll get 2 values for y when you substitute each of the 2 x-values into any of the 2 original equations.
That's how simple this is.
NEVER follow any of the other "respondent's" suggestions, unless you want to CONFUSE yourself and/or wish to spend a lot of time doing a ton of work.
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