SOLUTION: Hello! How can I find the focus and the directrix of the following equation: (y+2)^2=-12(x-5) Thank you!

Question 1072508: Hello! How can I find the focus and the directrix of the following equation: (y+2)^2=-12(x-5)
Thank you!
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
(y+2)^2 = -12(x-5)
:
This is an equation of a parabola in standard form, this parabola opens to the left since p is negative
:
The standard form is
:
( y - k )^2 = 4 * p * ( x - h )
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The vertex is (h, k) = (5, -2)
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Note that p = -12 / 4 = -3
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Focus = (h + p, k) = (5-3, -2) = (2, -2)
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Directrix is x = h - p = 5 - (-3) = 8
:

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