SOLUTION: Identify the type of conic section whose equation is given and find the vertices and foci. 1) x^2=y+1 2) 4x^2+4x+y^2=0

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Identify the type of conic section whose equation is given and find the vertices and foci. 1) x^2=y+1 2) 4x^2+4x+y^2=0      Log On


   

Question 1069496: Identify the type of conic section whose equation is given and find the vertices and foci.
1) x^2=y+1
2) 4x^2+4x+y^2=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2=y%2B1
y=x%5E2%2B1
Parabola
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4x%5E2%2B4x%2By%5E2=0
4%28x%5E2%2Bx%29%2By%5E2=0
%28x%5E2%2Bx%29%2By%5E2%2F4=0
%28x%5E2%2Bx%2BA%29%2By%5E2%2F4=A
%28x%2Bb%29%5E2%2Fa%5E2%2By%5E2%2F4=1
Ellipse, a,b,and A are stand-ins for non-zero constants needed to complete the square and show that the equation is an ellipse.