SOLUTION: x^2-3x-4>0 solve and write in interval notation
Algebra.Com
Question 1066507: x^2-3x-4>0 solve and write in interval notation
Found 2 solutions by josgarithmetic, Boreal:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
(-infinity, -1) OR (4, infinity)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x^2-3x-4=0
(x-4)(x+1)= 0
x= 4
x=-1
-1 and 4 are critical points. They divide the number line into three areas: test less than the smallest, between them, and greater than the largest.
For x <-1 try -2. f(-2) >0
between the two points, try 0 f(0)< 0, does not work
greater than 4, try 5 f(5)=6
(-1, 4)
RELATED QUESTIONS
solve the inequality and write in interval notation :... (answered by lwsshak3)
solve inequality and write answer in interval notation... (answered by KMST)
solve and write the answer in set builder notation or interval notation... (answered by Fombitz)
solve the quadratic inequality. Write the solution set in interval notation.... (answered by Edwin McCravy)
solve:
2-3x<6 and 2x+1>4
write the solution set in interval... (answered by stanbon)
solve the inequality and write the answer in interval notation... (answered by stanbon)
Solve the inequality. Write the solution set in interval notation.
2(x+6)+3 ≥ 4+3x
(answered by josgarithmetic,MathTherapy)
Solve the inequality -2(x-3)((x+4)^2)(x-11)<0 and write in interval notation. (answered by lwsshak3)
x^2 - 7x + 10 < 0
solve the following inequality and write the solution in interval... (answered by lwsshak3)