SOLUTION: Write the equation for the quadratic in standard form. With the focus at (6,2), the vertex at (6,-2) and the directrix line at y=-6. I know that the answer is y=x^2/10-6x/5+2/5

Question 1056473: Write the equation for the quadratic in standard form. With the focus at (6,2), the vertex at (6,-2) and the directrix line at y=-6.
I know that the answer is y=x^2/10-6x/5+2/5 but I don't have any idea how to reach this solution!! PLEASE HELP MEEE
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
Something is wrong with what you have stated above.
Either

is not the answer or else the vertex is not (6,-2)
The vertex of any parabola is a point on the parabola
and therefore must satisfy the equation of the parabola.
However, (6,-2) DOES NOT satisfy the equation!

Proof that it doesn't:

That is clearly false.
The parabola that you say is the answer
has vertex (6,-16/5),
focus (6,-7/10),
and directrix y = -57/10.
------------------------
The parabola that has focus at (6,2), vertex at (6,-2)
the directrix line at y=-6, has this equation:

I would have shown you how to get that, but since the
answer you said is correct is incorrect, I thought
I'd better wait until I was sure you had everything
correct before doing it. If you want to discuss it
with me, you may do so in the thank-you note form
below and I'll get back to you by email.
Edwin

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