SOLUTION: write an equation of the parabola with the given characteristic. focus (0,-1) directrix: y = 1

Question 1056075: write an equation of the parabola with the given characteristic.
focus (0,-1) directrix: y = 1
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Need to Know:
the vertex form of a Parabola opening up(a>0) or down(a<0),

where(h,k) is the vertex and x = h is the Line of Symmetry ,
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)
|
focus (0,-1) directrix: y = 1
the focus is (h,k + p)
k + p = -1 focus y = -1
k - p = 1 directrix: y = 1
k = 0, p = -1, a = -1/4
V(0,0)
|

RELATED QUESTIONS
18. Write an equation of a parabola with the given focus and directrix. Focus-(0,3),... (answered by ewatrrr)

Write an equation of the parabola with the given characteristic. vertex: (0,0)... (answered by ewatrrr)

write an equation of the parabola with the given characterists focus: (0,-4) directrix:... (answered by stanbon)

What are the focus and directrix of the parabola with the equation y = 1/12x2? focus: (answered by MathLover1)

Write the equation of the parabola with given focus (0,-5) and directrix:... (answered by josgarithmetic)

find the equation of the parabola with the given focus and directrix. focus... (answered by josgarithmetic,greenestamps)

Write an equation of a parabola with the given focus and directx. focus (0, 3);... (answered by ewatrrr)

Write an equation of the parabola with directrix x=-1 and focus (1,-2). (answered by josgarithmetic)

find an equation of the parabola with focus (2,-3) and directrix... (answered by josgarithmetic)