SOLUTION: sketch the hyperbola and label the vertices,foci,and asymptot of x²/16-y²/4=1
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Question 1047761: sketch the hyperbola and label the vertices,foci,and asymptot of x²/16-y²/4=1
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Need to Know:
Standard Form of an Equation of an Hyperbola opening right and left is:
with C(h,k) and vertices 'a' units right and left of center, 2a the length of the transverse axis. e = c/a.
Foci are = c- units right and left of center along y = k & Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a
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x²/16-y²/4=1
C(0,0)
vertices 'a' units right and left of center C(0,0)
V(4,0) and V(-4, 0)
|
Foci are = c- units right and left of center C(0,0) along y = k
c = 2√5
F( 2√5, 0) and F(-2√5, 0)
|
Asymptotes Lines passing thru C(0,0), with slopes m = ± b/a
m = ± 2/4 =± 1/2
y = ±(1/2)x
Sketch in the Hyperbola opening right and left
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