SOLUTION: Example: Please help me solve this equation: if f(x)={{{ (3x^2+x)/2x }}} for x=!0 {{{f(0)=k}}} and if ƒ is continuous at x = 0,

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Question 1044993: Example: Please help me solve this equation: if f(x)= for x=!0

and if ƒ is continuous at x = 0, then k =
A) -3/2
(B) -1
(C) 0
(D) 1
(E) 3/2 answer here

Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
L'Hôpital's Rule
derivative of this is
(1/4x^2)[(2x)(6x+1)-(3x^2+x)*2}
=(1/4x^2){12x^2+2x-6x^2-2x}
=(1/4x^2)(6x^2)=6/4=3/2
E

Answer by ikleyn(52800)   (Show Source): You can put this solution on YOUR website!
.
Example: Please help me solve this equation: if f(x)= for x=!0

and if ƒ is continuous at x = 0, then k =
A) -3/2
(B) -1
(C) 0
(D) 1
(E) 3/2 answer here
~~~~~~~~~~~~~~~~~~~~~

The formulation is incorrect. (And the solution is incorrect as well).

The correct formulation and solution follow:


    You are given a function  f(x) = .
    Find the limit of the function at x-->0.


Solution. 


Factor x out parentheses in the numerator. Then cancel factor "x" in the numerator an denominator. You will get

lim    =  lim   =  lim    = .
x-->0              x-->0               x-->0

Notice that this result  lim =   is not in the list.
Nevertheless, this result is correct.
Everything in the list is incorrect.

The plot illustrates it:




Plot y =


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