SOLUTION: find the properties of parabola: 2x^2+5y=0 vertex: axis of symmetry focus directrix latus retum pls help

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Question 1043234: find the properties of parabola: 2x^2+5y=0
vertex:
axis of symmetry
focus
directrix
latus retum
pls help
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
5y=-2x%5E2
5y=-2%28x-0%29%5E2
-%285%2F2%29%28y-0%29=%28x-0%29%5E2
Vertical Symmetry Axis, x=0
Vertex (0,0)


4p=-%285%2F2%29, p being distance from vertex to focus and distance from vertex to directrix;
p=-5%2F8
The negative coefficient tells that parabola has vertex as a maximum point and focus is below vertex; and directrix is above the vertex.


Focus, ( -5/8, 0)
Directrix , (5/8, 0)


Endpoints for Latus Rectum occur for x=-5%2F8; find corresponding y values.



equation for parabola given focus point and directrix