SOLUTION: Determine the vertex,focus,directrix,and axis of symmetry of the parabola with the given equation.
1) y^2-5x+12y=-16
2) 5x^2+30x+24y=51
guys,i really need your help on thi
Algebra.Com
Question 1041166: Determine the vertex,focus,directrix,and axis of symmetry of the parabola with the given equation.
1) y^2-5x+12y=-16
2) 5x^2+30x+24y=51
guys,i really need your help on this. thanks :)
Found 2 solutions by solver91311, josgarithmetic:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Complete the square on
and rearrange into standard conics form:
Where
is the vertex and
is the distance from the vertex to the focus and from the vertex to the directrix. The
term is squared so this parabola has a horizontal axis of symmetry and a vertical directrix.
Hence, vertex at
,
so
, directrix at
, focus
, and axis of symmetry
You can do your own arithmetic to simplify the expressions for the directrix and the focus.
.
John

My calculator said it, I believe it, that settles it

Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
These example instructive videos should help, but also study your textbook sections about this:
vertex at the origin - how to derive parabola equation
same idea but different orientation and vertex not at the origin
Study this one first; how to change from general form into standard form
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