SOLUTION: A searchlight reflector is designed so that a cross section through it axis is a parabola with the light source at its focus. If the reflector is 80 cm in diameter and 40 cm deep,
Algebra.Com
Question 103470: A searchlight reflector is designed so that a cross section through it axis is a parabola with the light source at its focus. If the reflector is 80 cm in diameter and 40 cm deep, how far from the opening is the light source?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
a general equation for the parabola is (x-h)^2=4p(y-k)
where the vertex is located at (h,k) and p is the distance from vertex to focus
designating the bottom of the reflector as the origin (0,0); and letting 1 unit=40 cm makes the ends of the diameter (1,1) and (-1,1)
(x-0)^2=4p(y-0)^2 ... x^2=4py^2 ... 4p=x^2/y^2 ... 4p=1/1 ... 4p=1 ... 4p=40cm ... p=10 cm
10 cm from the vertex is 30 cm from the opening
RELATED QUESTIONS
A searchlight reflector is designed so that a crass section through its axis is a... (answered by AnlytcPhil)
A SEARCHLIGHT HAS A PARABOLIC REFLECTOR (HAS A CROSS SECTION THAT FORMS A BOWL) THE... (answered by Alan3354)
A SEARCHLIGHT HAS A PARABOLIC REFLECTOR (HAS A CROSS SECTION THAT FORMS A BOWL) THE... (answered by Alan3354)
A SEARCHLIGHT HAS A PARABOLIC REFLECTOR (HAS A CROSS SECTION THAT FORMS A BOWL) THE... (answered by josgarithmetic)
The filament of a light bulb is a thin wire that glows when electricity passes through... (answered by nerdybill)
A parabolic searchlight is 5ft across its opening. If the light source is located 2ft... (answered by ikleyn)
if an automobile headlight reflector is cut by a plane through its axis, the section is a (answered by ikleyn)
The light bulb of a parabolic reflector is placed at the focus of the reflector for... (answered by Alan3354,ikleyn)
light bulb of a parabolic reflector is placed at the focus of th reflector for better... (answered by josgarithmetic)