SOLUTION: I need your help again! I can't figure out how to do the graph or solve the equation on this problem. Graph the parabola (y+2)^2 + 6x + 3 = 0. Identift the vertex, focus, and t

Question 103288: I need your help again! I can't figure out how to do the graph or solve the equation on this problem.
Graph the parabola (y+2)^2 + 6x + 3 = 0. Identift the vertex, focus, and the equation of the directrix.
Help! This has totally lost me. You guys are awesome! Thanks for the help!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Graph the parabola (y+2)^2 + 6x + 3 = 0. Identify the vertex, focus, and the equation of the directrix.
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Write in vertex form:
(y+2)^2 = -6(x-(1/2))
Vertex: ((1/2),-2)
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4p=-6, so p =-3/2
Focus: ((1/2)-(3/2),-2) = (-1,-2)
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Directrix: x = (1/2)-(-3/2) ; x = 2
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Cheers,
Stan H.

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