SOLUTION: 13x^2+3y^2=39
Need focus of the given ellipse
smaller y value?
larger y value?
Algebra.Com
Question 1032832: 13x^2+3y^2=39
Need focus of the given ellipse
smaller y value?
larger y value?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
From
we divide by 39 and get
This is a "tall" ellipse.
c^2 = 13 - 3 = 10
so that the foci are at
(0, sqrt(10)) and (0, -sqrt(10))
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