SOLUTION: Could someone please help me with writing a conic equation in standard form for a hyperbola with vertices at (1,6) and (1,-2) and asymptotes at y=(4/3)x+2/3 and y=(-4/3)x+10/3. I

Question 1028772: Could someone please help me with writing a conic equation in standard form for a hyperbola with vertices at (1,6) and (1,-2) and asymptotes at y=(4/3)x+2/3 and y=(-4/3)x+10/3. I would appreciate any help!!!
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
The transverse axis should be parallel to the y-axis, and the center is at the point (1,2), the midpoint of the vertices (1,6) and (1,-2).
The standard form is then given by
<==> y-2 = +/-
For very large positive/negative x-values,
y-2 = +/-. (Suppress .
==> y = +/- + 2.
y = +/- + 2.
Hence let a = 4 and b = 3, and the standard form is
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