SOLUTION: Find the vertex, directrix,focus and the length of the latus rectan of the parabola y^2+4y+3x-4=0.sketch the graph.

SOLUTION: Find the vertex, directrix,focus and the length of the latus rectan of the parabola y^2+4y+3x-4=0.sketch the graph.

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Question 1024401: Find the vertex, directrix,focus and the length of the latus rectan of the parabola y^2+4y+3x-4=0.sketch the graph.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
y^2+4y+3x-4=0
, somewhat easy because right side contains a perfect square...

----completing the square using .

OR

You might want to know why I put the equation into that form, and not into "standard form".

Study this video lesson about equations of parabolas!
Deriving equation for a parabola if given directrix and focus and if vertex is not at Origin

Recognize that YOUR parabola has horizontal symmetry axis, and opens to the LEFT.
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