SOLUTION: Please help to solve this by hand, much appreciated and thanks a bunch.
ln(x/2)-ln(x-1)=ln1
Algebra.Com
Question 1021745: Please help to solve this by hand, much appreciated and thanks a bunch.
ln(x/2)-ln(x-1)=ln1
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
log1 = 0. Therefore:
log(x/2)-log(x-1) = 0
log(x/2)-log(x-1) = log(1/(x-1))+log(x/2) = log(x/(2(x-1))):
log(x/(2(x-1))) = 0
Cancel logarithms by taking exp of both sides:
x/(2(x-1)) = 1
Multiply both sides by 2(x-1):
x = 2(x-1)
Expand out terms of the right hand side:
x = 2x-2
Subtract 2x from both sides:
-x = -2
Multiply both sides by -1:
x = 2
Happy learning.
J
RELATED QUESTIONS
Please help to solve this by hand.
ln(x/2)-ln(x-1)=ln1
Workings very much... (answered by Fombitz)
Please help solve this equation:
ln〖(1/2〗 x)-ln〖(x-1)〗 =... (answered by fractalier)
ln (x+1) = lnx +... (answered by Alan3354)
1. Write x in terms of a , b and c
a) ln x = ln a + ln b - ln c
b) ln x = 2 ln a + 3... (answered by ankor@dixie-net.com)
-could you please help me in this problem
solve for x:
ln(x-1)=ln(x-2)-ln... (answered by josgarithmetic)
please help! i cant solve this log equation.
2 ln x+ ln(x+7) =3... (answered by jim_thompson5910)
please help - not sure how to solve when I end up with log fractions?
ln(x)- ln(x+1) = (answered by longjonsilver)
Solve
a)log(x+1) = log 6 - log x
b)ln(x-2) + ln(3) = ln(x+1)
Can you please help me... (answered by KMST)
Please help me to Solve:... (answered by jsmallt9)