SOLUTION: Find the vertex and focus and end points of the latus rectum of the parabola 9x^2-12x-36y-8=0

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Question 1018042: Find the vertex and focus and end points of the latus rectum of the parabola 9x^2-12x-36y-8=0
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!


Divide through by 9





Complete the square:

               
               

Add to both sides











h=2, 4p=4, p=1, k=-1/3

Vertex = (h,k) = 

Length of latus rectum = 4p = 4.
                          p = 1.

Distance from vertex to the focus = 

Distance from vertex to the directrix = p = 1

y-coordinate of vertex = , add p=1, get ,

so focus = .

x-coordinate of right endpoint of latus rectum = 
x-ccordinate of focus plus half of latus rectum's length,
2p, get 
  
x-coordinate of left endpoint of latus rectum = 
x-ccordinate of focus minus half of latus rectum's length,
2p, get 

y-coordinates of ends of latus rectum = same as y-coordinate
of focus, 

right end of latus rectum = 

right end of latus rectum = 

Directrix has equation y = y-coodinate of vertex minus p = 1
which is 

Directrix has equation 

blue line segment is latus rectum
green line is directrix
Upper point marked is focus
Lower point marked is vertex



Edwin

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