SOLUTION: Show that the poles of tangents of the circle {{{(x-p)^2+y^2=b^2}}} with respect to the circle {{{x^2+y^2=a^2}}} lie on the curve {{{(px-a^2)^2=b^2(x^2+y^2)}}}

SOLUTION: Show that the poles of tangents of the circle {{{(x-p)^2+y^2=b^2}}} with respect to the circle {{{x^2+y^2=a^2}}} lie on the curve {{{(px-a^2)^2=b^2(x^2+y^2)}}}

Algebra.Com

Question 1016115: Show that the poles of tangents of the circle with respect to the circle lie on the curve
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.

Very interesting, but much higher than the school math.

Not for this site.

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