SOLUTION: Circle tangent to the x-axis at (5, 0) and the y-axis at (0, -5).
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Question 1008150: Circle tangent to the x-axis at (5, 0) and the y-axis at (0, -5).
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Circle tangent to the x-axis at (5, 0) and the y-axis at (0, -5).
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Center is at (5,-5)
radius = 5
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Equation:
(x-5)^2 + (y+5)^2 = 5^2
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Cheers,
Stan H.
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