SOLUTION: I need help with this question, I keep coming up with the wrong answers. The equation of the ellipse that has a center at (8,2) , a focus at (11,2) , and a vertex at (13,2) , is

Question 1000242: I need help with this question, I keep coming up with the wrong answers.
The equation of the ellipse that has a center at (8,2) , a focus at (11,2) , and a vertex at (13,2) , is
(x−C)^2/ A^2 +(y−D)^2/ B^2 =1
where
A= 4
B= 6
C= 8
D= 2

2. The equation of the ellipse that has a center at (1,5) , a focus at (5,5) , and a vertex at (−4,5) , is
(x−C)^ 2/ A^2 +(y−D)^2/ B ^2 =1
where
A= 5
B= 4
C= 1
D= 5

Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Difficult to make the right kind of drawing here, but try making a sketch of the ellipse as described.

Distance from center (8,2) to a vertex (13,2) is , so .

Use the variable C as the distance from the center to either focus. Your exercise description
will mean that you have C=3.

You want to find B. The fact relating A, B, and C using C as the distance from center
to either focus, is , giving .
Evaluate the value for B^2.
-

The standard form equation can now be filled-in, giving you
.

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