# SOLUTION: Find the vertex of the parabola. f(x)=-3x^2+16.2x-20.8

Algebra ->  -> SOLUTION: Find the vertex of the parabola. f(x)=-3x^2+16.2x-20.8      Log On

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 386167: Find the vertex of the parabola. f(x)=-3x^2+16.2x-20.8Answer by lwsshak3(7679)   (Show Source): You can put this solution on YOUR website!f(x) =3x^2+16.2x-20.8 to find the x coordinate of the vertex, use the formula, x=-b/2a a=3, b=16.2 x=-16.2/2*3 =16.2/6=-2.7 to find the y-coordinate, substitute -2.7 for x in the given equation y=3*(-2.7)^2+16.2*-2.7-20.8 =-42.67 ans: coordinates of the vertex are (-2.7,-42.67) see the following graph note: you can also find the coordinates of the vertex by completing the square to come up with the form, y=(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.